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⺯ʽǸ߿c֮һ.Ҫ⺯ĻϣʃeZrng?

Ӗų

()֪f(2-cosx)=cos2x+cosx,f(x-1).

̽

[1](1)֪f(x)f(logax)= (a>0,a1,x>0),f(x)\ʽ.

(2)֪κf(x)=ax2+bx+c|f(1)|=|f(-1)|=|f(0)|=1,f(x)\ʽ.

DҪ麯еҪأֵꠦԃr֪?Ŀ.

֪RУú֪RرǶԡfúõȼתעⶨ.

˼SҪ]hĿȼת?

?1)]Ԫ;(2)ôϵ.

?1)t=logax(a>1,t>0;0

f(t)= (at-a-t)

f(x)= (ax-a-x)(a>1,x>0;0

(2)f(1)=a+b+c,f(-1)=a-b+c,f(0)=c

f(1)f(-1)f(0)ͬr1-1f(x)=2x2-1f(x)=-2x2+1f(x)=-x2-x+1f(x)=x2-x-1f(x)=-x2+x+1f(x)=x2+x-1.

[2]f(x)Rϵżx-1ry=f(x)DN(-20)б1]y=f(x)DһǶ(02)ҹ(-11)һ]f(x)\ʽDD.

DҪ麯֪ʶߡߵĻDԷֶκķҪ˼S.ˣֶκo.Ŀ. ֪RУżؼϵ߷.

˼SҪܸ]ۡۺ֪R׷.

뷽мSôϵʽ.

?1)x-1rf(x)=x+b

߹(-20).0=-2+bb=2f(x)=x+2.

(2)-1

߹(-11)1=a·(-1)2+2,a=-1

f(x)=-x2+2.

(3)x1rf(x)=-x+2

{֪f(x)= Dɶ.

Ӗ漰⼰ҪУ

1.ϵ֪ʽĹrôϵ;

2.Ԫݚ֪rf[g(x)]\ʽ]ԪʽϼrҲݚ;

3.η֪ĺʽýIķf(x);

⣬ڽоõۡȼתѧO.

2018ɿ2018qr/

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